2017-07-05から1日間の記事一覧
問題 Problem 48:Self powers The series, 1^1 + 2^2 + 3^3 + ... + 10^10 = 10405071317.Find the last ten digits of the series, 1^1 + 2^2 + 3^3 + ... + 1000^1000. 解答例 sum = 0 for i in range(1, 1001): sum += i ** i tempStr = str(sum) print(…