Project Euler 38

• 問題

Problem 38：Pandigital multiples
Take the number 192 and multiply it by each of 1, 2, and 3:

192 × 1 = 192
192 × 2 = 384
192 × 3 = 576
By concatenating each product we get the 1 to 9 pandigital, 192384576. We will call 192384576 the concatenated product of 192 and (1,2,3)

The same can be achieved by starting with 9 and multiplying by 1, 2, 3, 4, and 5, giving the pandigital, 918273645, which is the concatenated product of 9 and (1,2,3,4,5).

What is the largest 1 to 9 pandigital 9-digit number that can be formed as the concatenated product of an integer with (1,2, ... , n) where n > 1?

• 解答例

max = 0
for i in range(1, 10000):
    tempStr = []
    j = 1
    while True:
        tempStr.extend(list(str(i * j)))
        if len(tempStr) >= 9:
            if "".join(sorted(tempStr)) == '123456789':
                if max < int("".join(tempStr)):
                    max = int("".join(tempStr))
                    print(i)
            break
        j += 1

print(max)