- 問題
Problem 5:Smallest multiple
2520 is the smallest number that can be divided by each of the numbers from 1 to 10 without any remainder.
What is the smallest positive number that is evenly divisible by all of the numbers from 1 to 20?
- 解答例
def gcd(m, n): while n: m, n = n, m % n return m def lcm(m, n): return (m * n) // gcd(m, n) mul = 1 for x in range(1, 21): mul = lcm(mul, x) print(mul)