Project Euler 48

• 問題

Problem 48：Self powers
The series, 1^1 + 2^2 + 3^3 + ... + 10^10 = 10405071317.

Find the last ten digits of the series, 1^1 + 2^2 + 3^3 + ... + 1000^1000.

• 解答例

sum = 0
for i in range(1, 1001):
    sum += i ** i
tempStr = str(sum)
print(tempStr[len(tempStr) - 10::])